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21x^2-81x+44=0
a = 21; b = -81; c = +44;
Δ = b2-4ac
Δ = -812-4·21·44
Δ = 2865
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-81)-\sqrt{2865}}{2*21}=\frac{81-\sqrt{2865}}{42} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-81)+\sqrt{2865}}{2*21}=\frac{81+\sqrt{2865}}{42} $
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